Answer: The required probability of three consecutive successful launches is 91.27%.
Step-by-step explanation: Given that a satellite launch has a 97% chance of success.
We are to find the probability of three consecutive successful launches.
Let P(A) denotes the probability of the event of the success of the satellite launch.
Then, according to the given information, we have
\(P(A)=97\%=\dfrac{97}{100}=0.97.\)
Therefore, the probability of three consecutive successful launches will be
\(p\\\\=P(A)\times P(A)\times P(A)\\\\=0.97\times0.97\times0.97\\\\=0.912673\\\\=0.912673\times100\%\\\\=91.2673\%\\\\=91.27\%.\)
Thus, the required probability of three consecutive successful launches is 91.27%.
