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Ben has $3.40 consisting of quarters and dimes. How many coins of each kind does he have if he has 22 coins?


Show a system of equation to represent the word problem.

Verified Answer :

syed514

got d + q = 22 and 10d + 25q = 340??

Answer:

There are 8 quarters and 14 dimes.

Step-by-step explanation:

Let there are x quarters.

and y dimes.

Also as we know,

1 quarter= 0.25 dollar

Hence, x quarter= $ 0.25x

and 1 dime= $ 0.10

Hence,  y dimes= $ 0.10y

  • Ben has $3.40 consisting of quarters and dimes.

This means that:

                 0.25x+0.10y=3.40

Also, in non-decimal form it could be written as:

                  25x+10y=340

  • He has 22 coins

This means that:

                       x+y=22

Now on solving it graphically we see what is the point of intersection of the two lines or system of linear equations.

We get the point of intersection as: (8,14)

i.e. x=8 and y=14

Hence, there are 8 quarters.

and 14 dimes.

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