a team has won 60 percent of the 20 games it has playes so far this season. If the team plays a total of 50 games all season and wins 80 percent of the remaining games, then the percent of games it won for the entire season will be
So far team has won =(60/100)20 = 12 gamesTotal games played in season =5080 percent of the remaining games won = 80 percent of (50-20) = (80/100)30 = 24 games.Total game won this season = 36So, percent games won in the entire season = (36/50)*100=72%Answer (4)
Answer: Option '4' is correct.
Step-by-step explanation:
Since we have given that
Total number of games =50
Firstly, he played 20 games.
Percentage of games they won = 60%
Number of games they won is given by
\(\dfrac{60}{100}\times 20\\\\=0.6\times 20\\\\=12\)
Remaining number of games = 50-20=30
Percentage of remaining games they won = 80%
So, number of games they won is given by
\(\dfrac{80}{100}\times 30\\\\=0.8\times 30\\\\=24\)
So, total number of games they won is given by
12+24 = 36
So, Percentage of games they won for the entire season will be
\(\dfrac{36}{50}\times 100\\\\=36\times 2\\\\=72\%\)
Hence, Option '4' is correct.