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A kicker kicks a football toward the opponent's goal line during a game. The ball begins its flight with an initial velocity of 70 feet per second when it is kicked at a height of 2 feet by the kicker. To the nearest foot, what maximum height will the ball reach?


You may use the function:

h(t)=-16t^2+70t+2

AThe answer cannot be determined.
B79 feet
C981 feet
D129 feet ...?

Verified Answer :

16t^2 + 70t + 2
-b/2a gives maximum height
-70/-32
f(70/32) = 79

B79 Feet
syed514


h(t) = -16t^2 + 70t + 2 
h'(t) = -32t + 70 
0 = -32t + 70 
32t = 70 
t = 70/32 
t = 35/16 

Using either method, t = 35/16. 
h(35/16) = -16(35/16)^2 + 70(35/16) + 2 
h(35/16) = -16(1225/256) + 2450/16 + 2 
h(35/16) = -1225/16 + 2450/16 + 32/16 
h(35/16) = 1257/16 
So the maximum height is 1257/16 feet, which is 78.5625 feet. 

To the nearest foot, that's 79 feet. 

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