A ball is thrown from an initial height of 3 ft with an initial upward velocity of 27ft/s The balls height h (in feet) after t seconds is given by the following. h=3+27t-16t^2. Find all values of t for which the balls height is 13 ft. ...?

Verified Answer :

Answer:

t = 0.55 s and t = 1.14 s

Explanation:

as we know that height in terms of time is given as

\(h = 3 + 27t - 16 t^2\)

now we have to find the time at which its height is h = 13 ft

so here we can say

\(13 = 3 + 27 t - 16 t^2\)

\(16 t^2 - 27 t + 10 = 0\)

\(t = \frac{27 \pm \sqrt{27^2 - 4(16)(10)}}{2(16)}\)

\(t = \frac{27 \pm 9.43}{32}\)

\(t = 1.14, 0.55\)

so it will be at h = 13 ft height at t = 0.55 s and t = 1.14 s