conjugate of 8+4i ...?
8 + 4i × 8 - 4i / 8 - 4i64 - 16i^2 / 8 - 4i64 - 16 ( - 1 ) / 8 - 4i64 + 16 / 8 - 4i80 / 8 - 4i10 - 20i
The conjugate of any complex number in the formα + βiisα - βiSo the conjugate of 8 + 4iis 8 - 4i
