Verified Answer :
P(overtime wage) = 19/52 + 5/52 = 24/52
P(temp help wage) = 11/52 + 5/52 = 16/52
P(overtime or temp help) = P(overtime) + P(temp help)
= 24/52 + 16/52
= 40/52 = 10/13
The probability that the payroll for one week contained overtime wages or temporary help is \(\boxed{\frac{10}{13}}\).
Further explanation:
It is given that during a \(52\) week period, a company paid overtime wages for \(19\) weeks and hired temporary help for \(11\) weeks.
During \(5\) weeks, the company paid overtime and hired temporary help.
Calculation:
A company paid overtime wages for \(19\) weeks and \(5\) weeks during the \(52\) week period.
Therefore, the probability of overtime wages \(P(O)\) is calculated as follows:
\(\begin{aligned}P(O)&=\dfrac{19}{52}+\dfrac{5}{52}\\&=\dfrac{19+5}{52}\\&=\dfrac{24}{52}\end{aligned}\)
The probability of overtime wages is \(\frac{24}{52}\).
The same company hired temporary help for \(11\) weeks and \(5\) weeks during the \(52\) week period.
Therefore, the probability of temporary help \(P(H)\) is calculated as follows:
\(\begin{aligned}P(H)&=\dfrac{11}{52}+\dfrac{5}{52}\\&=\dfrac{11+5}{52}\\&=\dfrac{16}{52}\end{aligned}\)
The probability of temporary help is \(\frac{16}{52}\).
Now, the combined probability \(P\) that the payroll for one week contained overtime wages or temporary help is calculated by adding the probabilities of overtime wages and temporary help as follows:
\(\begin{aligned}P&=\dfrac{24}{52}+\dfrac{16}{52}\\&=\dfrac{24+16}{52}\\&=\dfrac{40}{52}\\&=\dfrac{10}{13}\end{aligned}\)
The probability that the payroll for one week contained overtime wages or temporary help is \(\boxed{\dfrac{10}{13}}\).
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Answer details:
Grade: Middle school
Subject: Mathematics
Chapter: Probability
Keywords: Probability, events, outcome, sample, experiment, equally likely, random, complementary events, joint probability, independent events, mutually exclusive events, conditional probability.