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Verified Answer :

antonsandiego

To make a first step you have to know the balanced form for neutralization formula: \(Mg(OH)2(aq)+2HCl(aq)--\ \textgreater \ 2H2O+Mg(aq)+Cl(aq)\)
According to this, you can calculate what you are being asked :\(0.0442molMg(OH)2(x)(2molHCl)/(1molMg(OH)2)=0.0885molHCl\)
Then we have : \(0.140MHCl=0.140(mol/L)HCl\)
Hope everything is clear, here is the exact answer you need : \(V=(0.0885molHCl)/(0.140(mol/L)HCl)=0.632LHCl\)

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