The dimensions of a smaller rectangle are 3 ft. by 9 ft. The dimensions of a larger rectangle are 5 ft. by 11 ft. Find the ratio of the perimeter of the larger rectangle to the perimeter of the smaller rectangle. Options are 11:9, 3:4, 4:3, and 5:3 ...?
perimeter of smaller rect = 2L + 2B = 23ft + 29ft = 2(3 + 9) ft
perimeter of bigger rect = 2L + 2B = 25ft + 211ft = 2(5 + 11) ft
perimeter of larger rect 2(3 + 9) ft 12 3
--------------------- = ----------- = ------ = -----
perimeter of smaller rect 2(5 + 11) ft 16 4
so their ratio is 3:4
Answer:
Option 3rd is correct
4: 3
Step-by-step explanation:
Perimeter(P) of rectangle is given by:
\(P =2(l+w)\)
where, l is the length and w is the width of the rectangle respectively.
Given that:
The dimensions of a smaller rectangle are 3 ft. by 9 ft.
Perimeter of smaller rectangle= 2(3+9) =2(12) = 24 ft.
It is also given that: The dimensions of a larger rectangle are 5 ft. by 11 ft.
Perimeter of Larger rectangle = 2(5+11) =2(16) = 32 ft.
We have to find the ratio of the perimeter of the larger rectangle to the perimeter of the smaller rectangle.
\(\frac{\text{Perimeter of the larger rectangle}}{\text{Perimeter of the Smaller rectangle}}\)
Substitute the given values we have;'
\(\frac{32}{24}=\frac{4}{3}\)
Therefore, the ratio of the perimeter of the larger rectangle to the perimeter of the smaller rectangle is, 4 : 3