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Please help me solve this word problem:

In a round-robin chess tournament, each player is paired with every other player once. The function shown below, models the number of chess games, "N", that must be played in a round-robin tournament with "t" chess players. In a round-robin chess tournament, 55 games were played. How many players entered the tournament?


N=t^2-t divided by 2.

Verified Answer :

syed514

solve 55=(t^2−t)/2 for t
t2−t=110
t2−t−110=0
(t−11)(t+10)=0


t=11

aramisdegaula1977

Answer:

t = 11

Step-by-step explanation:

From the equation that gives, the number of games you can get the number t of players who participated in the ronund-robin tormeo, is:


\(N = \frac{t ^ 2-t}{2}\)

\(55 = \frac{t ^ 2-t}{2}\)

\(110 = t ^ 2-t\)

\(t ^ 2-t -110 = 0\)

\((t-11) (t + 10) = 0\).  Then

\(t - 11 = 0\\t = 11\\t + 10 = 0\\t = -10\)


Since t cannot take negative values, then t = 11.

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