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Verified Answer :

Correct answer is E.

\(y= \frac{ax+b}{x+c} \\ \\ \lim_{x \to \infty} \frac{ax+b}{x+c}=2 \\ \\ \lim_{x \to \infty} \frac{ \frac{ax}{x} + \frac{b}{x} }{ \frac{x}{x} + \frac{c}{x} }=2 \\ \\ \lim_{x \to \infty} \frac{a + \frac{b}{x} }{ 1 + \frac{c}{x} }=2 \\ \frac{a + 0}{ 1 + 0 }=2 \\ \\ \frac{a}{1} =2 \\a=2 \\ \\x+c=0 \\-3+c=0 \\c=3 \\ \\a+c=2+3=5\)

lunaar2

Answer: 5

Step-by-step explanation:

Lim x-> a (ax+b)/x+c = a you know that a=2

Since the limit of x ->-3 equals infinity, you know that x =3.

Thus a+c = 5

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