Verified Answer :

\(\sin{ \frac{2\pi}{3}} = \frac{ \sqrt{3} }{2} \\ \\ \sin{ \frac{\pi}{3}} = \frac{ \sqrt{3} }{2} \\ \\ - \frac{\pi}{2} \leq \arcsin{ x} \leq \frac{\pi}{2} \\ \\ \arcsin{(\sin{ \frac{2\pi}{3}})}=\arcsin{( \frac{ \sqrt{3} }{2} )}=\frac{\pi}{3}\)

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