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If a loaded truck that can accelerate at 2 m/s2 loses its load and has one-third of its original mass, what acceleration can it attain if the same driving force acts on it?

Verified Answer :

m 2m/s^2 = 1/3 m a

2m/s^2  = 1/3 a (multiply other side by 3)

2m/s^2 * 3=  a

= 6 m/s^2

Hope this helps

Answer:

a₂ = 6 m/s²

Explanation:

Conceptual Analysis

We apply Newton's second law:

F=ma Formula (1)

m: mass  in kilograms (kg)

a: acceleration (m/s²)

F: force in Newtons (N)

Known Data

a₁ = 2 m/s²

m₁= m

m₂= (1/3)m

Problem development

We apply formula (1) for the two conditions given:

F₁ = m₁a₁ = m2

F₂ = m₂a₂= (1/3)ma₂

F₁ = F₂

m2 =  (1/3)ma₂   We divide by m on both sides of the equation

2 = (1/3)a₂

6 = a₂

a₂ = 6 m/s²