Suppose a treadmill has an average acceleration of 4.7 x 10^-3. A) how much does its speed change after five min? B )If the treadmill's initial speed is 1.7 m/s ,what will it's final speed be?
v1 - v0 = at
= 4.7 x 10^3 m/s^2 x 300s
= 1.4 x 10^6 m/s
hope this helps
Explanation:
Given that,
Acceleration of the treadmill, \(a=4.7\times 10^{-3}\ m/s^2\)
Time, t = 5 min = 300 s
Acceleration is given by :
\(a=\dfrac{v-u}{t}\)
(a) (v-u) is the change in speed.
\(v-u=a\times t\)
\(v-u=4.7\times 10^{-3}\times 300\)
\(v-u=1.41\ m/s\)
So, the change in speed of the treadmill is 1.41 m/s.
(b) Initial speed of the treadmill, u = 1.7 m/s
The final speed is given by using equation as :
\(v=u+at\)
\(v=1.7+4.7\times 10^{-3}\times 300\)
v = 3.11 m/s
Hence, this is the required solution.