since it is a first orderedlinear ODE first we look for M(t)=e^integral(2)=e^2t
then multiplying whole equation by M will give
d[(e^(2t))y]/dt=e^(5t) e^(2t)
d[(e^(2t))y]=e^(7t) dt
integrating both sides gives
(e^(2t))y=(e^(7t))/7 +C
solving the result for y gives
y= (e^(5t))/7 +C(e^(-2t)) that is the general solution of the diff. equ.
