The spring constant for the tungsten strip is 26 N/m
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Further explanation
Hooke's Law states that the length of a spring is directly proportional to the force acting on the spring.
\(\boxed {F = k \times \Delta x}\)
F = Force ( N )
k = Spring Constant ( N/m )
Δx = Extension ( m )
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The formula for finding Young's Modulus is as follows:
\(\boxed {E = \frac{F / A}{\Delta x / x_o}}\)
E = Young's Modulus ( N/m² )
F = Force ( N )
A = Cross-Sectional Area ( m² )
Δx = Extension ( m )
x = Initial Length ( m )
Let us now tackle the problem !
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Given:
extension of strip = x = 0.25 m
magnitude of force = F = 6.5 N
Asked:
the spring constant for the tungsten strip = k = ?
Solution:
We will use Hooke's Law to solve this problem:
\(F = k x\)
\(6.5 = k \times 0.25\)
\(k = 6.5 \div 0.25\)
\(\boxed {k = 26 \texttt{ N/m}}\)
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Learn more
- Young's modulus : https://brainly.com/question/6864866
- Young's modulus for aluminum : https://brainly.com/question/7282579
- Young's modulus of wire : https://brainly.com/question/9755626
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Answer details
Grade: College
Subject: Physics
Chapter: Elasticity
