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A cyclist maintains a constant velocity of

4 m/s headed away from point A. At some

initial time, the cyclist is 253m from point A.

What will be his displacement from his

starting position after 64 s?

Answer in units of m


What will be his position from point A after

that time?

Answer in units of m

Verified Answer :

JcAlmighty

The answer is 509 m.

Let point B be 253 m from point A. Let point C be 64 s away from point B.
Let d1 be the displacements from point A to point B and d2 and be the displacements from point B to point C
Step 1. Calculate the displacement from the point B after 64 s.
Step 2. Calculate the displacement from the point A by summing up two distances (d1 and d2).

Step 1.
v = d2/t
v = 4 m/s
d2 = ?
t = 64s
____
4 = d2/64
d2 = 64 * 4 = 256 m


Step 2:
d = d1 + d2
d1 = 253 m
d2 = 256 m
d = 253 + 256 = 509m

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