If a snowball melts so that its surface area decreases at a rate of 7 cm2/min, find the rate at which the diameter decreases when the diameter is 10 cm.
Surface area: S
radius: r
diameter: e
time: t
[dS/dt] = [dS/de][de/dt] => de/dt = [dS/dt] / [dS/de]
S = 4pir^2 = 4pi(e/2)^2 = pie^2 => dS/de =2pie
dS/dt = 7cm^2 / min
de / dt = [2pie] / [7cm^2/min] =[7cm^2/min] / [2pi*10cm] = 0.11 cm/min