Assuming the two move in opposite directions
a)
Distance between the two = 10x - (-8x); x is the time in seconds
D = 18x
At x = 2,
D = 36 ft
This is greater than the length of the cord so it will not be slack.
b) The cord is tight when the girls' distance is 30 ft
30 = 18x
x = 1.67 seconds
Allyson will be:
10 x 1.67 = 16.7 feet from her starting position
Adrian will be:
8 x 1.67 = 13.3 feet from her starting position
Part c requires the figure.