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Verified Answer :

syed514

they appear to be using the (2x) as the variable;
so,
e^(t) + t^2 ;
now fill in the interval [0,2x]

 e^(2x) + (2x)^2 -e^(0)

 D{t} [e(2x) +4x^2 - 1]

 2e^(2x) + 8x

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