DK7leb1aylaDiie DK7leb1aylaDiie

19-11-2016
Mathematics

Answered

For all x > 0 and y > 0, the radical expression:

√x divided by 3√x-√y is equivalent to.

3x + √xy divided by 9x-y.

SOLVE.

Verified Answer :

nobillionaireNobley nobillionaireNobley

21-11-2016

\(\frac{ \sqrt{x} }{3 \sqrt{x} - \sqrt{y} } = \frac{3x+ \sqrt{xy} }{9x-y} =\frac{3x+ \sqrt{xy} }{(3 \sqrt{x} - \sqrt{y})(3 \sqrt{x} + \sqrt{y})} \\ \sqrt{x} =\frac{ \sqrt{x} (3 \sqrt{x} + \sqrt{y}) }{(3 \sqrt{x} + \sqrt{y})} \\ \sqrt{x} = \sqrt{x} \\ 1=1\)

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