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Kyle has three short straws, four medium straws, and six long straws. If he randomly draws two straws, one at a time without replacement, what is the probability that both are short straws?

A1/26
B3/52
C6/169
D9/169

Verified Answer :

The right answer is A option.

Answer:

\(\frac{1}{26}\)

Step-by-step explanation:

Given : Kyle has three short straws, four medium straws, and six long straws.

To Find: . If he randomly draws two straws, one at a time without replacement, what is the probability that both are short straws?

Solution:

Short Straws = 3

Medium Straws = 4

Long Straws = 6

Total straws = 3+4+6=13

Now , Probability of getting short straw on first draw = \(\frac{\text{No. of short straws}}{\text{Total Number of straws}}\)

                                                                                      = \(\frac{3}{13}\)  

Now the straw is not replaced .

So, Total no. of straws = 12

No. of short straws = 2

Now probability of getting short straw on Second draw = \(\frac{\text{No. of short straws}}{\text{Total Number of straws}}\)

                                                                                      = \(\frac{2}{12}\)  

Now ,the probability that both are short straws = \(\frac{2}{12} \times \frac{3}{13}\)  

                                                                               = \(\frac{6}{156}\)  

                                                                               = \(\frac{1}{26}\)  

Thus Option A is correct.

Hence ,the probability that both are short straws is  \(\frac{1}{26}\) .