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150.0 g of AsF3 was reacted with 180.0 g of CCl4 to produce AsCl3 and CCl2F2. The theoretical yield of CCl2F2 produced, in moles, is?


a]0.7802 mol

b]1.274 mol

c]1.170 mol

d]0.5685 mol

e]1.705 mol

Verified Answer :

Nirina7

the general equation is 
   2AsF3   +   3CCl4  ----------->   2AsCl3   +  3CCl2F2
   2mol                                                             3mol
   n mol  ------------------------------------------------> ?        
n (AsF3) =m/M=  1.13mol
 
 so,        n/2 = x/3 implies x = 3n/2 = 3*1.13 / 2= 1.69 mol it is near 1.7
the answer is e]1.705 mol

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