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syed514

4a⁴ + 6a³b² + 2a²b³ => 2a²(2a² + 3ab² + b³) 

Answer:

\(=2\cdot{a^2}\cdot{(2\cdot{a^2}+3\cdot{a}\cdot{b^2}+b^3)}\)

Step-by-step explanation:

We can factor the common number terms, a terms and b terms. The common term is 2a².

\(=4\cdot{a^4}+6\cdot{a^3}\cdot{b^2}+2\cdot{a^2}\cdot{b^3}\)

\(=2\cdot{a^2}\cdot{(2\cdot{a^2}+3\cdot{a}\cdot{b^2}+b^3)}\)

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