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Solve. If there are X teams in a sports league and all the teams play each other twice, a total of N(x) gamers are played, where N(x)=x^2-x. A soccer league has 10 teams, each of which plays the others twice. If the league pays $46 per game for the field and officials, how much will it cost to play the entire schedule?

Verified Answer :

syed514

number of games is 90, so cost is

90×46=4140

Answer:

\(\$4140\)

Step-by-step explanation:

According to the problem, x refers to teams, and \(N(x)=x^{2}-x\) represents numbers of games played.

So, if there are 10 teams, we just have to replace this value for the x and calculate the number of games. Once we have it, we multiply all games by $46, which is the cost per game.

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This means that in the entire schedule there are 90 games. If each one costs $46, the whole schedule will cost:

\(90(\$46)=\$4140\)

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