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Verified Answer :

syed514

The derivative of your function is:  
1 + (1dy/dx + y) - 4y(dy/dx) = 0

2 + dy/dx + y - 4y(dy/dx) = 0

(2 + y) + dy/dx (1 - 4y) = 0

(dy/dx) = -(2 + y)/(1 - 4y)
 
and at point (2,1),

dy/dx = -(2 + 1)/(1 - 41)
          = -3 / -3
          = 1

 
Slope of tangent line = 1

nastassjamotro

the derivative is actually (-y-1)/(4y+x)
then you plug in the points (2,1) ==>
(-1-1)/(4*1+2) which equals -1/3
then you just plug in your info into a point-slope formula and get:
y-1=-1/3(x-2) which can then be reduced

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