Answer: a) Our camera is 1.2 times faster than friend's camera.
b) We can take 20 pictures while the rider is in the air.
Step-by-step explanation:
According to the given problem
a) 1 picture in our camera takes time =0.125 seconds
1 picture in friend's camera takes time =0.15 seconds
The rate of pictures taken by our camera=\(\frac{1}{0.125}\ picture\ per\ second\)
The rate of pictures taken by friend's camera=\(\frac{1}{0.15}\ picture\ per\ second\)
Now, scale factor by which our camera is faster then friend's camera=
\(\frac{\frac{1}{0.125}}{\frac{1}{0.15}}=\frac{0.15}{0.125}=1.2\)
Thus Our camera is 1.2 times faster than friend's camera.
b) Number of pictures we can take while the rider is in the air\(=\frac{2.5}{0.125}=20\) [āµDuration of motocross rider is in the air = 2.5 seconds.]
Thus we can take 20 pictures while the rider is in the air.
