Alright! To simply means to just put it as simple as it can be while still meaning the same thing. So, in this question you're simplifying:
\(\frac{6xy^{6}z^{2} }{2y^{2}z^{8}}\)
First, you divide the whole numbers:
\(\frac{6xy^{6}z^{2} }{2y^{2}z^{8}}\) → \(\frac{3xy^{6}z^{2} }{y^{2}z^{8}}\)
All you have to do now is cancel out the powers with their corresponding base. So you'll get the following:
\(\frac{3xy^{4}}{z^{6}}\)
