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Will, Micah and sue went to dinner. Will paid 1/3 of the dinner bill. Micah and sue paid in the ratio of 2:5. If sue paid $6 more Than Will, how much did the dinner cost

Verified Answer :

BellaWasHere

$21. If you take 2:5 and double it 4:10, 10 is 6 more than four, so you add the two up (14) and then you have 2/3s of the bill. then you divide 14 in two (7) and multiply 7 by three (21).

Answer : The dinner cost was, $ 42

Step-by-step explanation :

Let the dinner cost be, 'x'

Dinner cost paid by Will = @@MATH_TOKEN_0@@

Remaining dinner cost = @@MATH_TOKEN_1@@

The ratio of dinner cost paid by Micah and sue is 2:5

Dinner cost paid by Micah = @@MATH_TOKEN_2@@

Dinner cost paid by Sue = @@MATH_TOKEN_3@@

As, Sue paid dinner cost $6 more than Will.

That means,

\((\frac{10}{21}x)=\$ 6+(\frac{1}{3}\times x)\)

\((\frac{10}{21}x)-(\frac{1}{3}\times x)=\$ 6\)

\((\frac{1}{7}\times x)=\$ 6\)

\(x=\$ 6\times 7\)

\(x=\$ 42\)

Thus, the dinner cost was, $ 42

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