Answer:
The subscrip for O is 4
Explanation:
The first step for this question is to assume that we have 100 g of the unknown compound. If we have 100g then we will have:
2 g of H
32.7 g of S
65.3 g of O
The next step is find the moles for each atom. So, we have to use the molar mass of each atom.
1 g/mol of H
32 g/mol for S
16 g/mol for O
Now, we can find the moles if we divide by the molar mass:
\(2~g~H\frac{1~molH}{1~gH}=2~molH\)
\(32.7~g~H\frac{1~molS}{32~gS}=1.02~molS\)
\(65.3~g~H\frac{1~molO}{16~gO}=4.08~molO\)
Then we have to divide the smallest mol number, so:
\(\frac{2~molH}{1.02}=2~molH\)
\(\frac{1.02~molS}{1.02}=1~molS\)
\(\frac{4.08~molO}{1.02}=4~molO\)
So, the formula would be: \(H_2SO_4\) with a "4" for oxygen.
