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what is the total amount of heat required to completely melt 347 grams of ice at its melting point?
1)334 J
2) 1450 J
3) 116,000 J
4) 784,000 J

Verified Answer :

Answer: The correct answer is Option C.

Explanation: The heat required can be calculated by using the formula:

\(q=mL\)

where, q = heat required or released

m = mass of the substance

L = Latent heat

As, this process is the melting of ice, so latent heat of fusion is used:

\(H_2O(s)\rightleftharpoons H_2O(l)\)

Latent heat of fusion for ice is 334 kJ/kg

Mass of the object = 347 grams = 0.347 kg  (Conversion factor: 1kg = 1000 grams)

Putting the values in above equation, we get:

\(q=334kJ/kg\times 0.347kg\\\\q=115.9kJ\approx 116kJ\)

Converting kilo-joules into joules, we use the conversion:

1 kJ = 1000J

So, q = 116000J

Hence, the correct option is 3.

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