y-0=2(x+8) and y+4=2/3(x-6)
Recall that, at this section, we have no ‘shortcut rules’ for derivatives, andmust use the (limit) definition;f0(x) = limh→0f(x + h) − f(x)hBut, in this case, f is unusually simple; f(x) = −3. This meansf(anything) = −3
