How do u solve ax+b>cd
ax+b>cd
-b -b
-------------
ax>(cd)-b
/a /a
-------------
x=(cd)-b/a
now lets use some numbers
a>4
b>2
c>6
d>1/2
4x+2>6(1/2)
-2 -2
---------------
4x>3-2
4x>1
/4 /4
--------------
x>1/4
remember if you ever need anything or need a question answered you can just message me or post it on my profile
The required solution is \(x>\dfrac{cd-b}{a}\).
Given:
The given inequality is \(ax+b>cd\).
To find:
The solution to the given inequality.
Explanation:
We have,
\(ax+b>cd\)
Subtract \(b\) from both sides.
\(ax+b-b>cd-b\)
\(ax>cd-b\)
Divide both sides by \(a\).
\(\dfrac{ax}{a}>\dfrac{cd-b}{a}\)
\(x>\dfrac{cd-b}{a}\)
Therefore, the required solution is \(x>\dfrac{cd-b}{a}\).
Learn more:
https://brainly.com/question/12306534