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Verified Answer :

ax+b>cd
     -b   -b
-------------
ax>(cd)-b
/a      /a
-------------
x=(cd)-b/a        
                            
now lets use some numbers
a>4
b>2
c>6
d>1/2

4x+2>6(1/2)
    -2     -2
 ---------------
 4x>3-2
 4x>1
 /4    /4
--------------
 x>1/4
 
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The required solution is \(x>\dfrac{cd-b}{a}\).  

Given:

The given inequality is \(ax+b>cd\).

To find:

The solution to the given inequality.

Explanation:

We have,

\(ax+b>cd\)

Subtract \(b\) from both sides.

\(ax+b-b>cd-b\)

\(ax>cd-b\)

Divide both sides by \(a\).

\(\dfrac{ax}{a}>\dfrac{cd-b}{a}\)

\(x>\dfrac{cd-b}{a}\)

Therefore, the required solution is \(x>\dfrac{cd-b}{a}\).

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