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Vector A⃗ has a magnitude of 3.00 and is directed parallel to the negative y-axis and vector B⃗ has a magnitude of 3.00 and is directed parallel to the positive y-axis. Determine the magnitude and direction angle (as measured counterclockwise from the positive x-axis) of vector C⃗ , if C⃗ =A⃗ −B⃗ .


C = 6.00; θ = 270˚

C = 3.00; θ = 270˚

C = 6.00; θ = 90˚

C = 3.00; θ = 90˚

Vector A has a magnitude of 3.00 and is directed parallel to the negative y-axis and vector B has a magnitude of 3.00 and is directed parallel to the positive y class=

Verified Answer :

The correct
answer between all the choices given is the first choice, which is "C = 6.00; θ = 270˚". I am
hoping that this answer has satisfied your query and it will be able to help
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smmwaite

Answer

C = 6.00; θ = 270˚

Explanation

A vector is described by giving both its magnitude and direction.

A = 3.00; 270°

B = -3.00; 90°

C = A - B. From this expression, it can be seen that we have already reversed the direction of B. So vector C is in the direction of A.

C = A - B

C = 3.00 - (-3.00)

= 6.00


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