A gardener uses 1/3 of a liter of water to water 2/7 of a garden. Watering the entire garden at this rate will require _____ liters of water.
1 1/6 liters
1/3 x 3 =1 liter and 6/7 of the garden watered divide 1/3 by two to get 1/7 of the garden t. add together to get 7/7
Answer:
\(1\frac{1}{6}\) liter of water is needed to watering the entire garden at the given rate.
Step-by-step explanation:
Given : A gardener uses \(\frac{1}{3}\) of a liter of water to watering \(\frac{2}{7}\) of a garden.
Consider 1 Liter = 1 unit.
Hence, \(\frac{1}{3}\) of a liter = \(\frac{1}{3}\)
We need to find how many liters of water is needed to watering the entire garden at this rate.
Let the total garden be x parts then,
\(\frac{2}{7}x=\frac{1}{3} \times 1\)
\(\frac{2}{7}x=\frac{1}{3}\)
Dividing both side by \(\frac{2}{7}\) , we get,
\(x=\frac{1}{3} \div \frac{2}{7}\)
Applying \(a\div b=a\times \frac{1}{b}\) , we get,
\(x=\frac{1}{3} \times \frac{7}{2}\)
\(x=\frac{7}{6}\)
Rewriting improper fraction into mixed fraction, we get,
\(x=1\frac{1}{6}\)
Thus, \(1\frac{1}{6}\) liter of water is needed to watering the entire garden at the given rate.