Answer:
The value of a is -4.
Step-by-step explanation:
Since, two lines \(a_1 x+b_1 y=c_1\) and \(a_2 x+b_2 y=c_2\) are called parallel lines,
If \(\frac{a_1}{a_2}=\frac{b_1}{b_2}
eq \frac{c_1}{c_2}\)
If 3x + 6y = 4 and ax-8y = 12 are parallel lines,
Then, by the above property,
\(\frac{3}{a}=\frac{6}{-8}
eq \frac{4}{12}\)
\(\implies \frac{3}{a}=\frac{6}{-8}\)
By cross multiplication,
\(-24 = 6a\)
\(\implies -4=a\) ( Dividing both terms by 6}
Hence, the value of a is -4 for which 4 = 3x + 6y and ax – 8y = 12 are parallel.
