The correct answer to the question is \(336.98\times 10^4\ J\)
CALCULATION:
The acceleration of the truck is given as a = \(0.0083\ m/s^2\)
The mass of truck is given as m = 7000 kg.
The distance travelled by the truck S = \(5.8\times 10^{4}\ m\).
The force applied on the truck is calculated as -
Force F = mass × acceleration
= \(7000\ kg\times 0.0083\ m/s^2\)
= 58.1 N.
We are asked to calculate the work done .
The work done by a body is calculated as -
W = \(\vec F.\vec S\)
= \(FScos\theta\)
Here, \(\theta\) is the angle between force and displacement.
If \(\theta=0^{0}\), then W = FS
Hence, the work done by the truck W = FS
= \(58.1\ N\times 5.8\times 10^{4}\ m\)
= \(336.98\times 10^4\ J\)
Here, J ( joule ) is the unit of work.
