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Solve for x.


5x – 10 > 20 or 5x – 10 ≤ –15

A–5 ≤ x < 6
B–1 ≤ x < 6
Cx ≤ –5 or x > 6
Dx ≤ –1 or x > 6

Verified Answer :

Amphitrite1040

I'm going to go with letter D.

Answer:

\(\text{The solution is }x \leq -1\text{ or }x > 6\)

Step-by-step explanation:

Given the two inequalities  

\(5x - 10 > 20\text{ or }5x - 10 \leq -15\)

we have to solve the above two for x.

\(5x - 10 > 20\)

Adding 10 on both sides

\(5x>20+10\)

\(5x>30\)

Divide throughout by 5, we get

\(x>\frac{30}{5}=6\)

\(\text{second inequality:}\thinspace 5x - 10 \leq -15\)

\(5x - 10 \leq -15\)

Adding 10 on both sides

\(5x \leq -15+10\)

\(5x\leq -5\)

\(x \leq -1\)

hence, the solution is

\(x \leq -1\text{ or }x > 6\)

which is required solution.

Option D is correct.

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