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Verified Answer :

cornbreadking

well,you can use the pythagorean theorem,which is a^2+b^2=c^2 to solve for x.

bartdrinksmalk

\(x+31\) and \(2x-59\) are congruent sides

So we have
\(2x-59=x+31\)
⇒\(x-59=31\)
⇒\(x=90\)

Plug in:
\(x+31=90+31=121\)
\(2x-59=2(90)-59=180-59=121\)
\(x-7=90-7=83\)

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