In Δ ABC the value of cos B is \(\frac{12}{13}\) .
What is the trigonometric ratio?
Trigonometric ratios can be calculated by taking the ratio of any two sides of the right-angled triangle.
The basic Trigonometric ratios are :
- sin θ = \(\frac{Perpendicular}{Hypotenuse}\)
- cos θ = \(\frac{Base}{Hypotenuse}\)
- tan θ = \(\frac{Perpendicular}{Base}\)
- sec θ = \(\frac{Hypotenuse}{Base}\)
- cosec θ = \(\frac{Hypotenuse}{Perpendicular}\)
- cot θ = \(\frac{Base}{Perpendicular}\)
According to the question
In Δ ABC ,
Perpendicular for ∠B = 5
Base for ∠B = 12
Hypotenuse for ∠B = 13
Cos B = \(\frac{Base}{Hypotenuse}\)
Cos B = \(\frac{12}{13}\)
Hence, In Δ ABC the value of cos B is \(\frac{12}{13}\) .
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