The vertex of the given equation is \((1,-5)\).
Given:
The given equation is:
\(y=(x-1)^2-5\) ...(i)
Explanation:
The vertex form of a quadratic equation is:
\(y=a(x-h)^2+k\) ...(ii)
Where, a is the constant and (h,k) is the vertex.
On comparing (i) and (ii), we get
\(h=1\)
\(k=-5\)
Therefore, the vertex of the given equation is \((1,-5)\).
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