Answer
41 views
Explanation
To solve this, we are going to use the exponential function:
\(f(t)=a(1+b)^t\)
\(f(t)\) is the final number of views after \(t\) weeks
\(a\) is the number of views
\(b\) is the growing rate in decimal form
\(t\) is the time in weeks
We know from our problem that the number initial views was 20 and the growing rate is 20%, so \(a=20\) and \(r=\frac{20}{100} =0.2\). Let's replace the values in our exponential function:
\(f(t)=a(1+b)^t\)
\(f(t)=20(1+0.2)^t\)
\(f(t)=20(1.2)^t\)
Now to find the number of views expected four weeks from now, we just need to replace t with 4, so \(t=4\)
\(f(t)=20(1.2)^t\)
\(f(4)=20(1.2)^4\)
\(f(t)=41.472\)
And rounded to the nearest whole number:
\(f(t)=41\)
