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Which series of transformations takes the graph of f(x)=3x−8 to the graph of g(x)=−3x+12 ?


A.) reflect the graph about the y-axis and translate 4 units down


B.) reflect the graph about the y-axis and translate 4 units up


C.) reflect the graph about the x-axis and translate 4 units down


D.) reflect the graph about the x-axis and translate 4 units up

Verified Answer :

 reflect the graph about the x-axis and translate 4 units down 

D.) reflect the graph about the x-axis and translate 4 units up

Explanation:

Before to identify the correct choice, let's see the definition of reflection along the x-axis and the y-axis:

1- A reflection of \(f(x)\) about the x-axis can be done by changing \(f(x)\) into \(-f(x)\). This means that if we have a line in the form

\(y=mx+q\)

a reflection about the x-axis can be done by changing the function into

\(y=-mx-q\)

2- A reflection of \(f(x)\) about the y-axis can be done by changing \(f(x)\) into \(f(-x)\). This means that if we have a line in the form

\(y=mx+q\)

a reflection about the x-axis can be done by replacing all the x with -x:

\(y=-mx+q\)

Back to our exercise:

The original function is \(f(x)=-3x-8\). The final function is \(g(x)=-3x+12\). First of all, we immediately notice that both the signs of m and q have been changed: therefore, it must be a reflection about the x-axis, so we can discard option B.

The reflection of f(x) about the x-axis is

\(f'(x)=-3x+8\)

We see that the y-intercept is +8, while in g(x) the y-intercept is +12. In order to match the two functions, we must translate f'(x) up by 4 units, so that we get

\(f'(x)+4=-3x+8+4=-3x+12\)

which corresponds to g(x). So, the correct option is D.