A number cube is tossed and one card is randomly drawn. Find P(3, yellow) (BTW There are 5 cards 3 yellow 2 blue) The answer choice are: A. 1/30 B. 1/25 C.3/25 D.1/10
Answer: \(\dfrac{1}{10}\)
Step-by-step explanation:
Probability =\(\dfrac{\text{favorable outcomes}}{\text{total outcomes}}\)
Given : A number cube is tossed and one card is randomly drawn.
Total outcomes for cube = 6
Total outcomes fro cards = 5
Number of yellow cards = 3
Event 1 : drawing 3 on cube .
\(P(E_1)=\dfrac{1}{6}\)
Event 2 : drawing a yellow card .
\(P(E_2)=\dfrac{3}{5}\)
Since both events are independent then probability of getting 3 on cube and a yellow card is \(P(E_1)\times P(E_2)\)
i.e. \(\text{P(3, yellow)}=\dfrac{1}{6}\times\dfrac{3}{5}=\dfrac{1}{10}\)
Hence, P(3, yellow)= \(\dfrac{1}{10}\)