Simple....
to solve for this-->>
Using the formula for area of a right triangle-->> \(\frac{1}{2} bh\)
For both triangles it'd be the same formula-->>\(\frac{1}{2} 4*3\) (The base is split in half as it is two triangles)
=6
Now since there's two triangles-->>6+6=12\(yd^{2}\)
Thus, your answer.
