Answer:
\(y_{max} = 1208.8 m\)
Explanation:
As we know that flare is shot at an angle of 62.9 degree
and the initial speed is given as
\(v_i = 173 m/s\)
now we have
\(v_y = v sin\theta\)
\(v_y = 173 sin62.9\)
\(v_y = 154 m/s\)
now the maximum height of the flare is given as
\(y_{max} = \frac{v^2}{2g}\)
\(y_{max} = \frac{154^2}{2(9.81)}\)
\(y_{max} = 1208.8 m\)
