\(4x+4y=0\)
\(2x+y=-2\)
We'll use \(2x+y=-2\)⇒\(y=-2x-2\)
Plug into the other formula:
\(4x+4(-2x-2)=0\)
⇒\(4x-8x-8=0\)
⇒\(-4x-8=0\)
⇒\(-4x=8\)
⇒\(x=-2\)
Plug \(x\) in to get \(y\):
\(y=-2(-2)-2\)
⇒\(y=4-2\)
⇒\(y=2\)
So our solution is \(x=-2\), \(y=2\)
