Verified Answer :
Each tile is 3 in. × 2 in. = \(\frac{1}{4}\) ft × \(\frac{1}{6}\) ft
The area of a tile is \(\frac{1}{4}*\frac{1}{6}=\frac{1}{24}\) ft²
The area of the room is 1215=180 ft²
The number of tiles is 180÷\(\frac{1}{24}\)=18024=4320
which is 432 sets of 10 tiles.
The total cost is $1.20/set * 432 sets = $518.40
Cost of the tile to the room will be ₹518.40
What is area of the rectangle?
- Length of the rectangle be l
- Breadth of the rectangular be b
- Area of the rectangle is given by A = l × b sq.units
We know that 1 ft = 12 inch
12 ft = 1212 = 144 inch
15 ft = 1512 = 180 inch
Dimension of the rectangular room = 12ft by 15ft = 144in × 180in
Area of the rectangle = length × breadth
The area of the room in sq.inch is given by 144180 = 25920 sq. in
The area of one tile is 3inches 2inches = 6 sq.in
The total number of tiles required is 25920/6 = 4320 tiles
cost of 10 tiles = $1.20
To find cost of 4320 tiles
cost of 4320 tiles = (4320 × 1.20)/10
= ₹518.40
Hence, Cost of the tile to the room will be ₹518.40
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