Web Analytics

Verified Answer :

bartdrinksmalk

First, let's write 6.4 as a fraction to make it a bit easier to work with.
\(\int\ {\frac{32}{5}e^{-3x+6}} \, dx\)
\(=\frac{32}{5} \int\ {e^{-3x+6}} \, dx\)
Use u-substitution:
\(u=-3x+6\)
\(du=-3dx\)
So we now have
\(\frac{32}{5}*-\frac{1}{3} \int {-3e^{-3x+6}} \, dx\)
\(=-\frac{32}{15} \int {e^{u}} \, du\)
\(=-\frac{32}{15}e^{u}+C\)
\(=-\frac{32}{15}e^{-3x+6}+C\)

(If you want the answer to have a decimal, then \(-\frac{32}{15}\) is -2.133333...)

Related Questions