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Kari bought 3 boxes of cookies to share with a book club. Each box contains 12 cookies. The expression 36/p represents the number of cookies that each person, p, can have if the cookies are divided equally. Which evaluations of the expression are correct? Check all that apply.

If p=5, then each person would get 6 cookies, with 4 cookies left over.

If p=7, then each person would get 5 cookies, with 1 cookie left over.

If p=8, then each person would get 4 cookies, with 3 cookies left over.

If p=10, then each person would get 3 cookies, with 6 cookies left over.

If p=11, then each person would get 3 cookies, with 3 cookies left over.

If p=12, then each person would get 3 cookies, with 1 cookie left over.

If p=15, then each person would get 2 cookies, with 6 cookies left over.

Verified Answer :

P=7 because 7 x 5 is 35, 36-35=1 left over

Answer:

p=7, p=10, p=11 and p=15

Step-by-step explanation:

The given expression is

\(\frac{36}{p}\)

This expression represents the number of cookies that each person, p, can have if the cookies are divided equally.

If p=5, then

\(\frac{36}{5}=7+\frac{1}{5}\)

It means each person would get 7 cookies, with 1 cookies left over.

If p=7, then

\(\frac{36}{7}=5+\frac{1}{5}\)

It means each person would get 5 cookies, with 1 cookies left over.

If p=8, then

\(\frac{36}{8}=4+\frac{4}{5}\)

It means each person would get 4 cookies, with 4 cookies left over.

If p=7, then

\(\frac{36}{7}=5+\frac{1}{5}\)

It means each person would get 5 cookies, with 1 cookies left over.

If p=10, then

\(\frac{36}{10}=3+\frac{6}{5}\)

It means each person would get 3 cookies, with 6 cookies left over.

If p=11, then

\(\frac{36}{11}=3+\frac{3}{5}\)

It means each person would get 3 cookies, with 3 cookies left over.

If p=12, then

\(\frac{36}{12}=3\)

It means each person would get 3 cookies, with 0 cookies left over.

If p=15, then

\(\frac{36}{15}=2+\frac{6}{5}\)

It means each person would get 2 cookies, with 6 cookies left over.

Therefore, the correct evaluations of the expression are p=7, p=10, p=11 and p=15.